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How to reshape array based on another array with nan values

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Michael Burnett
Michael Burnett 2020 年 11 月 2 日
コメント済み: Michael Burnett 2020 年 11 月 2 日
I want to see if there is a specific function that will help me do this:
I have a 10x1 array.
a = [2 6 5 4 7 2 3 2 3 1];
I would like to reshape it to fit the same shape as logical array b (with nan values as 0).
b = [1 1 1 0;1 1 1 1;1 0 1 1]
Is there an easy way to reshape my array in that mold?

採用された回答

Bruno Luong
Bruno Luong 2020 年 11 月 2 日
編集済み: Bruno Luong 2020 年 11 月 2 日
a = [2 6 5 4 7 2 3 2 3 1]
b = [1 1 1 0;1 1 1 1;1 0 1 1]
A = nan(size(b'));
A(b'==1) = a;
A = A.'

その他の回答 (1 件)

Abolfazl Chaman Motlagh
Abolfazl Chaman Motlagh 2020 年 11 月 2 日
b=logical(b);
A=zeros(size(b));
A(b)=a;
A(~b)=nan(sum(~b,'all'),1);
output:
A =
2 4 2 NaN
6 7 3 3
5 NaN 2 1
  2 件のコメント
Michael Burnett
Michael Burnett 2020 年 11 月 2 日
Lol, I'm quite new to MATLAB, so this is very helpful. Thanks

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