Infinite Loop with conditional statement if

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Hdez
Hdez 2020 年 11 月 2 日
コメント済み: Ameer Hamza 2020 年 11 月 2 日
Hello everyone.
I am new to Matlab and I got a question that I have solved but I think it is wrong. It is supposed to be solved with the Conditional statement if
Question: Write a programme that will keep asking the user of the code to enter a value. The code will return the square root of the entered value. The programme should be implemented using an inifinite for loop that will be broken when the user does not need to enter another value.
Answer:
clc
clear all
for i=1:1:inf
a= input ('Enter a value to be square rooted:');
r= sqrt (a);
fprintf ('The square root of %g is:\n', a)
end
r
I don't know where to add the if, also, is the if condition the reason while the infinite value will be broken? Thank you

回答 (2 件)

Abdolkarim Mohammadi
Abdolkarim Mohammadi 2020 年 11 月 2 日
The for loop can be broken using break statement.
for
if
break
end
end
  1 件のコメント
Hdez
Hdez 2020 年 11 月 2 日
clc
clear all
for i=1:1:inf
a= input ('Enter a value to be square rooted:');
r= sqrt (a);
if r==10
break;
end
fprintf ('The square root of %g is:\n', a)
end
I have written this in stead but it does not break

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Ameer Hamza
Ameer Hamza 2020 年 11 月 2 日
編集済み: Ameer Hamza 2020 年 11 月 2 日
You are not printing the square-root value and also not breaking the loop.
clc
while 1
a= input ('Enter a value to be square rooted:');
r= sqrt (a);
fprintf ('The square root of %g is: %f\n', a, r)
m = input ('Do you want to enter another number (Type ''n'' to stop):', 's');
if lower(m)=='n'
break;
end
end
  4 件のコメント
Hdez
Hdez 2020 年 11 月 2 日
I input 110 but it doesn't break at all
Ameer Hamza
Ameer Hamza 2020 年 11 月 2 日
You gave the condition r==100, Try giving condition r > 100
if r > 10

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