It follows the END that terminates the definition of the function "NumIntF" error

function f =NumIntF(xi,xf)
 h=0.001;
 N=(xf-xi)/h;
 ii=1;
 while(ii<= (N+1))
 if(ii==1);
 x(ii)=xi;
 y(ii)= cos(x(ii))*exp(sin(x(ii)))*h;
 else
 x(ii)=x(ii-1)+h;
 y(ii)=y(ii-1)+cos(x(ii))*exp(sin(x(ii)))*h;
 end
 ii=ii+1;
 end
 f= y(N+1);

end

[Ameer Hamza]

How are you running this code?

[Abdullah Ahmad]

Just By normally clicking on run

Answer 1

[Alan Stevens]

Put

xi = 0;
xf = pi; % or whatever your desired start and end values are.
f = NumIntf(xi,xf)

in a script and run that - it worked for me.

[Abdullah Ahmad]

Thank YOu it worked :)

Answer 2

[Alan Stevens]

Just change

f=y(N+1);

to

f= y(end);

[Abdullah Ahmad]

Still showing the same error