ODE error Array indices must be positive integers or logical values.

5 ビュー (過去 30 日間)
Luis Montenegro
Luis Montenegro 2020 年 11 月 1 日
コメント済み: Ameer Hamza 2020 年 11 月 1 日
I've been trying to get this working, but every time I run the script I get an error saying "Array indices must be positive integers or logical values and points to the dxdt(2) for the error. This is the code:
t = (0:0.1:5);
condIni = [0;0;0;0;0];
[T,Y] = ode45(@Grua,t,condIni);
x1 = Y(:,1);
x2 = Y(:,2);
x3 = Y(:,3);
x4 = Y(:,4);
plot(t,x1,'-b','linewidth',2)
xlabel('tiempo (s)');
ylabel('desplazamiento (m)');
figure()
plot(t,x2,'-b','linewidth',2)
xlabel('tiempo (s)');
ylabel('Velocidad (m/s)');
figure()
plot(t,x3,'-b','linewidth',2)
xlabel('tiempo (s)');
ylabel('desplazamiento angular (rad)');
figure()
plot(t,x4,'-b','linewidth',2)
xlabel('tiempo (s)');
ylabel('Velocidad angular (rad/s)');
function dxdt = Grua(t,x)
L=3;
m=100;
M=30;
r1=0.05;
r2=0.1;
R=0.15;
ct=0.01;
cp=0.1;
c=1;
K=10;
Kb=9;
Lb=1e-2;
Rb=6.2;
J=1e-3;
E=100;
N=r1/r2;
g=9.81;
dxdt(1) = x(2);
dxdt(2) = (K*L*x(5)-L*ct*x(2)+N*R*cp*x(4)-L*N^2*R^2*c*x(2)+L*R*N*m*g*x(3))/(L(M*N^2*R^2+J));
dxdt(3) = x(4);
dxdt(4) = ((-cp*x(4)-m*g*L*x(3))/L^2) -((m*R*L*N)/L^2)*((K*L*x(5)-L*ct*x(2)+N*R*cp*x(4)-L*N^2*R^2*c*x(2)+L*N*R*g*m*x(3))/(L(M*N^2*R^2+J)));
dxdt(5) = (E-Kb*x(2)-x(5)*Rb)/Lb;
dxdt = dxdt';
end

採用された回答

Ameer Hamza
Ameer Hamza 2020 年 11 月 1 日
You missed the multiplication operator in the denominator
dxdt(2) = ../(L*(M*N^2*R^2+J));
%^ this is missing
dxdt(4) = ../(L*(M*N^2*R^2+J)));
%^ this is missing
  2 件のコメント
Luis Montenegro
Luis Montenegro 2020 年 11 月 1 日
Oh gosh... There is a lot of stuff I completely missed that. Thank you so much
Ameer Hamza
Ameer Hamza 2020 年 11 月 1 日
I am glad to be of help!

サインインしてコメントする。

その他の回答 (1 件)

KSSV
KSSV 2020 年 11 月 1 日
The indices for an array in MATLAB should be posititve integers or logicals. If you give fractions, 0, negative as index it will throw error.
Example:
A = rand(1,10) ;
A(1) % no error
A(10) % no error
A(0) % error as index cannot be zero
A(-1) % error, as index cannot be negative
A(0.5) % error, as index cannot be fraction
idx = A<0.5 ;
A(idx) % idx has 0, 1 they are logicals, so allowed
In your case..check where the index is taking not allowed value. Learn to debug your code...Read about debugging.

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by