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Drawing a segment of a circle

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Bojan
Bojan 2011 年 4 月 27 日
コメント済み: zain ul haq 2019 年 12 月 23 日
I would like to draw a segment of a circle (like a slice of a pizza) but cannot find an easy way to do it.
I am currently drawing triangles using fill function but ideally I need one side of the triangle to be curved. Is there a way to specify a curvature of a line? Thanks B

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the cyclist
the cyclist 2011 年 4 月 27 日
There are several files in the File Exchange that will do what you want. Here is one:
Also, here is a simple function that could be modified to draw just a segment:
function h = circle(x,y,r,nsegments)
if nargin<4
nsegments=50;
end
hold on
th = 0:2*pi/nsegments:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
h = plot(xunit, yunit);
hold off
end
  1 件のコメント
poonam tailor
poonam tailor 2015 年 1 月 31 日
Sir i need sector's center point. As i need a mid region of a circles sector for cluster head selection.

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その他の回答 (1 件)

Matt Fig
Matt Fig 2011 年 4 月 27 日
Here is another function to do it. It returns the handle to the patch object so that the color can be set or whatever.
function P = plot_arc(a,b,h,k,r)
% Plot a circular arc as a pie wedge.
% a is start of arc in radians,
% b is end of arc in radians,
% (h,k) is the center of the circle.
% r is the radius.
% Try this: plot_arc(pi/4,3*pi/4,9,-4,3)
% Author: Matt Fig
t = linspace(a,b);
x = r*cos(t) + h;
y = r*sin(t) + k;
x = [x h x(1)];
y = [y k y(1)];
P = fill(x,y,'r');
axis([h-r-1 h+r+1 k-r-1 k+r+1])
axis square;
if ~nargout
clear P
end
Now from the command line:
P = plot_arc(pi/4,3*pi/3,9,-4,3);
set(P,'edgecolor','b','linewidth',4)
  7 件のコメント
Ron Beck
Ron Beck 2018 年 2 月 26 日
Is it possible to have a curve at the bottom instead of a point?
zain ul haq
zain ul haq 2019 年 12 月 23 日
Sir, can I plot the segmet with height too, I need to plot like a 3d slice of a cake

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