how do u plot this between 0 and 2
syms n x
F = symsum(1/factorial(n),n,1,5)

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Ameer Hamza
Ameer Hamza 2020 年 10 月 30 日

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There is no 'x' in your expression inside symsum(). I guess you are tyring to plot taylor series of exp(x). Try this
syms n x
F = symsum(x^n/factorial(n),n,0,5);
fplot(F, [0 2])

9 件のコメント

DARREN O BRIEN
DARREN O BRIEN 2020 年 10 月 30 日
its a power series which is close to the taylor but still a little different but i was wrong its (n+1)(n+1)-(n-2)/n!
so if u can show how to plot that i would be gratefull
Ameer Hamza
Ameer Hamza 2020 年 10 月 30 日
Where is 'x' in your series?
Ameer Hamza
Ameer Hamza 2020 年 10 月 30 日
Can you show the mathematical form of your equations?
DARREN O BRIEN
DARREN O BRIEN 2020 年 10 月 30 日
i was right the first time its 1/n! but the maths behind is in the picture its too long too write
Ameer Hamza
Ameer Hamza 2020 年 10 月 30 日
If you just want to plot 1/n! then you will just get a straight line becuase there is no dependency on 'x'
syms n x
F = symsum(1/factorial(n),n,0,5);
fplot(F, [0 2])
DARREN O BRIEN
DARREN O BRIEN 2020 年 10 月 30 日
if u put the numbers in 1, 1/2,1/6,1/24,1/120, 1/720. thats obviously not a straight line
Ameer Hamza
Ameer Hamza 2020 年 10 月 30 日
But the original question had a reference to symsum() and x range from [0 2], so that was confusing. If you just want to plot 1/n! then you can do it like this
n = 1:5;
y = 1./factorial(n);
plot(n, y)
DARREN O BRIEN
DARREN O BRIEN 2020 年 10 月 30 日
sorry for the confusion but in the question we are given its plot the corresponding polynomial over the range 0 ≤ x ≤ 2
Ameer Hamza
Ameer Hamza 2020 年 10 月 31 日
But how do you define the polynomial from the series of 1/n!. If you look at my original answer. It does create a polynomial.

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