ommiting blanks in a string

how would i write a code to print each line of the string array G omitting any trailing blanks and blanks in-between letters

Answer 1

[Thorsten]

s = ['   hallo  a b c'; 'asdsdf v vvvv  '];
for i = 1:size(s, 1)
   disp(s(i, setdiff(1:length(s(i,:)), findstr(' ', s(i,:)))))
end

Answer 2

[José-Luis]

your_array = char(randi([32 127],100,10));

for ii = your_array'
    sub_set = ii(ii ~= char(32))'
end

Answer 3

[Image Analyst]

Use strtrim(). From the help:

S = strtrim(str) returns a copy of string str with all leading and trailing white-space characters removed. A white-space character is one for which the isspace function returns logical 1 (true).

Code:

for k = 1:size(yourString, 1)
   fprintf('%s', strtrim(yourString(k,:)));
end

Answer 4

[Jan]

This means, that you want to conserve the leading spaces, correctly?

Deleting all spaces would be:

s = strrep(s, ' ', '');  % Works for cell strings also

Trailing spaces:

s = deblank(s);

Conserve leading spaces - assuming that you have a cell string:

for iC = 1:numel(C)
  S     = C{iC};
  first = find(isletter(S), 1);
  C{iC} = [S(1:first - 1), strrep(S, ' ', '')];
end

And an equivalent approach work for a string also.