Create an array of file names produced by system('dir /S *.ext')

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bugguts99
bugguts99 2011 年 4 月 27 日
コメント済み: Seung-Goo Kim 2022 年 10 月 14 日
Hi there,
I know that you can search directories and sub-directories to provide a list of file names that meet a particular criteria using the code below:
[status,list]=system('dir /S *.mp3');
My question is: is it possible to create an array from the file names generated this way in order to create a loop for further processing??
Thanks in advance...

採用された回答

Richard Alcock
Richard Alcock 2011 年 4 月 27 日
You can use textscan to split the multiple lines of output from the system command into a cell array.
[status, list] = system( 'dir /B /S *.mp3' );
result = textscan( list, '%s', 'delimiter', '\n' );
fileList = result{1}
Note that I've added /B to the dir command to make the output easier to parse.
  2 件のコメント
bugguts99
bugguts99 2011 年 5 月 2 日
Thanks - works a treat!
franco otaola
franco otaola 2016 年 10 月 7 日
is there any possibility of extract the name without the extension? thanks

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その他の回答 (1 件)

Sven Mesecke
Sven Mesecke 2011 年 4 月 27 日
What's wrong with the MATLAB function 'dir'? You can add wildcards like .mp3 and get a struct array in return, whose name field can easily be converted into a cell array of filenames:
a=dir('S/*.ext');
b={a.name}
Otherwise there's a nice tool on MATLAB Central that uses regular expressions for dir: http://www.mathworks.com/matlabcentral/fileexchange/16216-regexpdir
  5 件のコメント
nvmnghia
nvmnghia 2020 年 2 月 23 日
Why can't we use
b = [a.name]
here?
Seung-Goo Kim
Seung-Goo Kim 2022 年 10 月 14 日
@nvmnghia you can try it yourself on your computer. But now MATLAB supports something like Jupyter notebook on a virtual environment:
pwd
ans = '/users/mss.system.TC8Vlw'
unix('echo"" > thisfile1.txt'); unix('echo"" > ThatFile-1234.txt');
a = dir('*.txt')
a = 2×1 struct array with fields:
name folder date bytes isdir datenum
b = [a.name]
b = 'ThatFile-1234.txtthisfile1.txt'
This will create a very wide character array by horizontally concatenating cated character arrays (i.e., file names). Then it becomes another problem to access each file. You usually can't do vertical concatenation because often the file names have different number of characters.
b = cat(1,a.name)
Error using cat
Dimensions of arrays being concatenated are not consistent.
So, this is why you want to cast them into a cell array, instead of a character array, as @Sven Mesecke wrote above.

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