How can I solve it: Matrix dimensions must agree.

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Aimee Jin
Aimee Jin 2020 年 10 月 25 日
コメント済み: Walter Roberson 2020 年 10 月 25 日
function A = matrixCSums(M)
% M is a numeric matrix and A has the same size as M.
% Each element in A is the sum of the corresponding element in M and all
% the elements above it. Example:
% M = [ 1 3; ... A = [ 1 3; ...
% 4 5; ... 5 8; ...
% -7 2] then -2 10]
% Do NOT use any built-in functions other than size
if M ==[]
A=[];
else
A(1,:)=M(1,:); %initial row of A
[nr,nc]=size(M);
for i=2:nr
A(i,:)=A(i-1,:)+M(i,:);
end
end
When I call the function:
M = [ 1 3; 4 5; -7 2];
A = matrixCSums(M)
it says:
Error using ==
Matrix dimensions must agree.
Error in matrixCSums (line 9)
if M ==[]

採用された回答

Alan Stevens
Alan Stevens 2020 年 10 月 25 日
Replace
if M ==[]
with
if isempty(M)

その他の回答 (1 件)

drummer
drummer 2020 年 10 月 25 日
if M == []
A(M == []) = [];
else
% rest of your code here.
end
Hope that helps.
Cheers
  1 件のコメント
Walter Roberson
Walter Roberson 2020 年 10 月 25 日
M == [] is going to fail unless M is empty (but will work if M is a different size of empty).

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