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char to double data type

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Waqas Siddique
Waqas Siddique 2020 年 10 月 24 日
編集済み: dpb 2020 年 10 月 25 日
How do I convert the following
164x11 char=
'03-Jan-2018'
'07-Jan-2018'
'07-Jan-2018'..
to 164x11 double=
'03-Jan-2018'
'07-Jan-2018'
'07-Jan-2018'
I want the elements to remain the same and just change the data type
  2 件のコメント
Ameer Hamza
Ameer Hamza 2020 年 10 月 24 日
No, it is not possible. And why do you want to do that?
Waqas Siddique
Waqas Siddique 2020 年 10 月 24 日
I have 4 variables
a=164x11 double
b=164x11 double
c=164x11 double
d=164x11 char
I am using the command to display
e=[a,b,c,d]
so I get an error
Error using datetime/horzcat (line 1335)
All inputs must be datetimes or date/time character vectors or date/time strings.

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回答 (2 件)

dpb
dpb 2020 年 10 月 24 日
Deprecated (and not recommended) would be
dn=datenum(yourdatechararray,'dd-mmm-yyyy');
which, of course, returns the datenum associated with the date; to get the representation use datestr. But, dn is a double.
The present (and recommended) way to handle dates is to use datetime instead --
dt=datetime(yourdatechararray,'InputFormat','dd-MMM-yyyy');
NB: the input format string representations are NOT the same between the two.
dt is its own class of datetime array, not a double. But, one can do comparisons of equality, greater/less than, etc., as well as plot and such have been extended to recognize the class as inputs.
  4 件のコメント
Walter Roberson
Walter Roberson 2020 年 10 月 24 日
fprintf() or compose() -- you will probably find compose() easier.
dpb
dpb 2020 年 10 月 24 日
編集済み: dpb 2020 年 10 月 25 日
Or, depending upon what you mean, exactly, by "display", put them in a table and the ML table data display will handle automagically...
ADDENDUM:
Oh, I see Steven L already suggested via timetable..."great minds ..." :)

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Steven Lord
Steven Lord 2020 年 10 月 24 日
I recommend turning the character data representing dates into a datetime array and using that datetime array along with your double data to create a timetable.

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