Drawing an arc between two elements?

I want to draw an arc (given its centre and its radius) between two elements.

For example the case given in the image below. I would like to draw an arc (of radius 0.5 (as an example) and the centre de point P drawed) strictly between those two lines

What is the general case of doing it? I mean, in this particular case there are two lines, but I would like a method that would work for whatever elements between I'd want to draw an arc (between a circle and a line, between two circles...etc).

[KSSV]

You have not commented on your previous question...

https://in.mathworks.com/matlabcentral/answers/621553-finding-the-intersec-point-using-interx?s_tid=prof_contriblnk

If the answer worked for you..you have to acknowledge the users who have helped you. With out closing that question, you are asking another question similiar ti it?

[ErikJon Pérez Mardaras]

sorry, my fault

Answer 1

[KSSV]

L1=[1 3;
1 6]

L2=[-2 2;
8 -1]

P=InterX(L1,L2);

L = [L2(:,1) P L1(:,2)] ;
p = polyfit(L(1,:),L(2,:),2) ;

xi = linspace(min(L(1,:)),max(L(1,:))) ;
yi = polyval(p,xi) ;

figure
hold on
plot(L1(1,:),L1(2,:),'r')
plot(L2(1,:),L2(2,:),'b')
plot(P(1),P(2),'ro')
plot(xi,yi,'k')

[ErikJon Pérez Mardaras]

The arc I`m looking for is that one in green:

[KSSV]

Okay...get the angles...th1 and th2.

      th = linspace(th1,th2);
      xc = r*cos(th) ;
      yc = r*sin(th) ;
You can use slope formula to get angles.

[ErikJon Pérez Mardaras]

I tried it out in a blank grpah just to try. th1 and th2 are 90º. I tried that code and it didn`t work

The code I entered was that:

axis equal
hold on

th = linspace(0,90);
xc = 0.5*cos(th) ;
yc = 0.5*sin(th) ;



plot(xc,yc,'r')

[KSSV]

Your th is in degrees.....

th = linspace(0,pi/2);
xc = 0.5*cos(th) ;
yc = 0.5*sin(th) ;



plot(xc,yc,'r')

[ErikJon Pérez Mardaras]

Thanks! I didn't realised. However, how do you stablish the centre of the arc? In the example given, the arc is drawn with a 0.5 radius, from 0º to 90º. But the centre is the 0.

How can I make the centre to be, for example, the coordinate 2,10? or the intersec point of two lines?

[KSSV]

xc = 2+0.5*cos(Th) ; 
yc = 10+0.5*sin(th) ;

[ErikJon Pérez Mardaras]

thanks!