shift to left sequence
5 ビュー (過去 30 日間)
古いコメントを表示
hi. i want to shift my sequence to left but there is a problem.
clc;
clear all;
close all;
% our domain in 11
n = 0:10;
x = cos (n*pi/12);
% shift x to left 2 unit
x2 = [x 0 0];
y = 2*x;
y2 = 2*x2;
d = y - y(-2:11-2);
% do should be = 0
stem (n,y2)
the problem is i can't enter a negative value to y(-2:9);
how can i change that line?
-------------------------------------------------------
errore:
Array indices must be positive integers or logical values.
Error in Untitled (line 14)
d = y - y(-2:11-2);
1 件のコメント
David Hill
2020 年 10 月 21 日
I have no idea what you want to do. Please provide and example. [1 2 3 4] goes to what?
回答 (1 件)
Ameer Hamza
2020 年 10 月 21 日
編集済み: Ameer Hamza
2020 年 10 月 21 日
n = 0:10;
x = cos (n*pi/12);
y = circshift(x, 2)
3 件のコメント
Ameer Hamza
2020 年 10 月 21 日
Negative indexes are not supported in MATLAB like they do in python. MATLAB supports something like the following if that helps
n = 0:10;
x = cos (n*pi/12);
y = x([end-1:end 1:end-2])
参考
カテゴリ
Help Center および File Exchange で Characters and Strings についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!