Constant Power Load (CPL) block Simscape Electrical

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Krupa Prag
Krupa Prag 2020 年 10 月 13 日
編集済み: Aniruddh Maini 2022 年 9 月 17 日
I currently am designing a Buck-Boost Converter using the blocks from powerlib Simulink.
I would like to add a CPL to the circuit. However, this block exists in another library and is not compatible with my current circuit design.
Any suggestions on how to modify the circuit to include this component or would the entire circuit have to be rebuilt using Simscape Electrical library. I would like to use this environment with the reinforcement learning functionalities.
  3 件のコメント
Pemendra Kumar Pardhi
Pemendra Kumar Pardhi 2020 年 10 月 13 日
you can also refer concept same as power electronics circuits for LED.
Krupa Prag
Krupa Prag 2020 年 10 月 14 日
Thank you for your response.

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回答 (2 件)

Joel Van Sickel
Joel Van Sickel 2020 年 10 月 14 日
Hello Krupa,
you can build your own constant power load using a controlled source. use a controlled current source and calculate the current using P/V = I. To break the algebraic loop, put a low pass filter between this calculation and the controlled current source. You can create a low pass filter with the transfer function block. Have the numerator = [1] and the denominator = [1/(2*pi*100) 1]. This will not be an ideal constant power load, but will be quite close to a constant power load and can be implemented in any number of circuit simulators.
Regards,
Joel
  1 件のコメント
Krupa Prag
Krupa Prag 2020 年 10 月 19 日
Thank you for your response.

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Aniruddh Maini
Aniruddh Maini 2022 年 9 月 17 日
編集済み: Aniruddh Maini 2022 年 9 月 17 日
Hi Joel
Can you please eleborate your answer more clearly or can you please come up with a diagram which clearly depicts how to model a buck converter with Constant power load because I am facing really a hard time modelling a buck converter with CPL which should dissipate constant power?
Thanks

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