# What should I do in order to make my code plot like this?

1 回表示 (過去 30 日間)
Minhao Wang 2020 年 10 月 12 日

sap = input('Select a program: 1. Arts; 2. Science; 3. Engineering: ');
nb(1) = 2000;
mir = 0.0625/12;
mc = 200;
for B = 2 : 216
nb(B) = (nb(B-1)+1) + ((nb(B-1)+1) * mir) + mc;
end
fprintf('At the end of 18 years you will have saved \$ %f \n',nb(B))
if sap == 1
os1(1) = 5550;
air = 0.07;
for A = 2 : 22
os1(A) = (os1(A-1) + 1) + ((os1(A-1) + 1) * air);
end
x1 = os1(19)+ os1(20) + os1(21) + os1(22);
fprintf('The cose of a 4-year college tuition fee is \$ %f\n',x1)
if nb(216) > x1
disp('Congratulations!!!! You have saved enough.')
elseif nb(216) < x1
s1 = x1 - nb(216);
fprintf('The saving is \$ %f\n',s1)
end
end
I need the year be exactly 0 to 18 years, so I can compare two lines like this.
I tried to use
time = 1:18
plot(time,nb(1:216),time,os1(1:22))
But this will cause erroe message 'Vector must be the same length.'

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### 回答 (1 件)

Mathieu NOE 2020 年 10 月 12 日
hi
this is the modified code
sap = input('Select a program: 1. Arts; 2. Science; 3. Engineering: ');
nb(1) = 2000;
mir = 0.0625/12;
mc = 200;
for B = 2 : 216 % 216 = nb of monthes for 18 years
nb(B) = (nb(B-1)+1) + ((nb(B-1)+1) * mir) + mc;
end
fprintf('At the end of 18 years you will have saved \$ %f \n',nb(B))
if sap == 1
os1(1) = 5550;
air = 0.07;
for A = 2 : 22
os1(A) = (os1(A-1) + 1) + ((os1(A-1) + 1) * air);
end
x1 = os1(19)+ os1(20) + os1(21) + os1(22);
fprintf('The cose of a 4-year college tuition fee is \$ %f\n',x1)
if nb(216) > x1
disp('Congratulations!!!! You have saved enough.')
elseif nb(216) < x1
s1 = x1 - nb(216);
fprintf('The saving is \$ %f\n',s1)
end
% plot
x_axis_years = 1:18; % define x axis
ind_nb_years = (1:18)*12;
nb_years = nb(ind_nb_years);
plot(x_axis_years,nb_years,'-+b',x_axis_years,x1*ones(1,length(x_axis_years)),'r'); grid on
title('my Title');
xlabel('Years');
end

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