フィルターのクリア

What should I do in order to make my code plot like this?

1 回表示 (過去 30 日間)
Minhao Wang
Minhao Wang 2020 年 10 月 12 日
回答済み: Mathieu NOE 2020 年 10 月 12 日
sap = input('Select a program: 1. Arts; 2. Science; 3. Engineering: ');
nb(1) = 2000;
mir = 0.0625/12;
mc = 200;
for B = 2 : 216
nb(B) = (nb(B-1)+1) + ((nb(B-1)+1) * mir) + mc;
end
fprintf('At the end of 18 years you will have saved $ %f \n',nb(B))
if sap == 1
os1(1) = 5550;
air = 0.07;
for A = 2 : 22
os1(A) = (os1(A-1) + 1) + ((os1(A-1) + 1) * air);
end
x1 = os1(19)+ os1(20) + os1(21) + os1(22);
fprintf('The cose of a 4-year college tuition fee is $ %f\n',x1)
if nb(216) > x1
disp('Congratulations!!!! You have saved enough.')
elseif nb(216) < x1
s1 = x1 - nb(216);
fprintf('The saving is $ %f\n',s1)
end
end
I need the year be exactly 0 to 18 years, so I can compare two lines like this.
I tried to use
time = 1:18
plot(time,nb(1:216),time,os1(1:22))
But this will cause erroe message 'Vector must be the same length.'
Can someone please help me with this?

回答 (1 件)

Mathieu NOE
Mathieu NOE 2020 年 10 月 12 日
hi
this is the modified code
sap = input('Select a program: 1. Arts; 2. Science; 3. Engineering: ');
nb(1) = 2000;
mir = 0.0625/12;
mc = 200;
for B = 2 : 216 % 216 = nb of monthes for 18 years
nb(B) = (nb(B-1)+1) + ((nb(B-1)+1) * mir) + mc;
end
fprintf('At the end of 18 years you will have saved $ %f \n',nb(B))
if sap == 1
os1(1) = 5550;
air = 0.07;
for A = 2 : 22
os1(A) = (os1(A-1) + 1) + ((os1(A-1) + 1) * air);
end
x1 = os1(19)+ os1(20) + os1(21) + os1(22);
fprintf('The cose of a 4-year college tuition fee is $ %f\n',x1)
if nb(216) > x1
disp('Congratulations!!!! You have saved enough.')
elseif nb(216) < x1
s1 = x1 - nb(216);
fprintf('The saving is $ %f\n',s1)
end
% plot
x_axis_years = 1:18; % define x axis
ind_nb_years = (1:18)*12;
nb_years = nb(ind_nb_years);
plot(x_axis_years,nb_years,'-+b',x_axis_years,x1*ones(1,length(x_axis_years)),'r'); grid on
title('my Title');
xlabel('Years');
end

カテゴリ

Help Center および File ExchangeLanguage Fundamentals についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by