doubt in for Loop

Hi,

Now i want to execute a formula;

if e+t<L

.......(some logic)

wherein the size of e= 8x1 doubt

t=28x1 doubt

L=8x1 doubt.

Is there anyway I can execute this line.

Please help.

Answer 1

[Walter Roberson]

for K = 1 : numel(e)
    if all(e(K) + t < L)
        .......(some logic)
    end
end

[Anurag Gupta]

Hi Sir,

it shows error Matrix dimension must agree.

is it because dimensions of all variables are different?

thanks and regards.

[Walter Roberson]

for K = 1 : numel(t)
    if all(e + t(K) < L)
        .......(some logic)
    end
end

[Anurag Gupta]

Hi Sir,

I am getting this error 'Index exceeds the number of array elements (8).' as e is a matrix with 8 elements and whenever the value of K reaches 9 it shows 'Index exceeds the number of array elements (8).' error.

Sir I will try to explain my entire problem in brief and it would be great if you can spare time to read it and provide me with a solution.

so now, I have a Matrix A of size 34x2 double,of which each row represents a arc. depending on this I have value of t 34x1 double, of which each row represents time taken to travel in each arc. now I have a constraint such that e and l can be of size 8x1 double.

now I want to remove few arcs from A such that: (e+t<l) now since t and e are of different sizes it is proving to be difficult to work them out under one for loop. it would be great if you can help.

Regards,

Anurag Gupta

[Walter Roberson]

The code I posted,

for K = 1 : numel(t)
    if all(e + t(K) < L)
        .......(some logic)
    end
end

does not index e, so you will not get an error about the number of elements in e.