フィルターのクリア

How to check if a user entered input will form a valid function handle?

4 ビュー (過去 30 日間)
Mohit Kumar
Mohit Kumar 2020 年 10 月 8 日
コメント済み: Ameer Hamza 2020 年 10 月 8 日
The user enters a character vector (in the edit text field of Appdesigner). I want to convert it into a function handle. I am doing this by concatenating it with '@(x,y)', making the function compatible with matrices and then using str2func. However, I want to be able to check if the input by the user is valid. Also, the function entered by the user must have its variables as x and/or y only.
For example, if the entered input is 'log(x)+sin(y)' the entry is valid whereas if the input is 'log(x)+*sin(y)' it should show an error.
Thanks,
Mohit.
  2 件のコメント
Ameer Hamza
Ameer Hamza 2020 年 10 月 8 日
Why 'log(x)+-sin(y)' is invalid? It is a valid MATLAB syntax.
Mohit Kumar
Mohit Kumar 2020 年 10 月 8 日
Okay, that was a poor mistake on my part. Something like log(x)+*sin(y). Have made the same change in the question.

サインインしてコメントする。

採用された回答

Ameer Hamza
Ameer Hamza 2020 年 10 月 8 日
You may try exception handling to check if a function handle is valid
x = 'x^2+2+SUM(x)'; % SUM is not a valid function in MATLAB
f = str2func(['@(x) ' x]);
is_correct = true;
try
f(0); % or some other value
catch ME
is_correct = false;
error(ME.message); % throw an error, remove this line if you don't
% want an error appearing in command window.
end
  2 件のコメント
Mohit Kumar
Mohit Kumar 2020 年 10 月 8 日
Thanks! Seems to be working great as far I tested.
Ameer Hamza
Ameer Hamza 2020 年 10 月 8 日
I am glad to be of help! Let me know in the comment if there is some edge case where it fails.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeArgument Definitions についてさらに検索

製品


リリース

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by