Fourier Series`of an Even function

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Salik Mallick
Salik Mallick 2020 年 10 月 4 日
コメント済み: Star Strider 2020 年 10 月 11 日
Why is a0 a value if pi when It shouldn't be?
%% Problem 17.5
display('Problem 17.5')
syms n t
Wo = 1;
T = 2*pi;
n = 1:10;
a0 = (1/T)*[int(-14,t,-pi,0) + int(7,t,0,pi)]
an = (2/T)*[int(-14*cos(n*Wo*t),-pi,0) + int(7*cos(n*Wo*t),0,pi)]
bn = (2/T)*[int(-14*sin(n*Wo*t),-pi,0) + int(7*sin(n*Wo*t),0,pi)]
  3 件のコメント
Salik Mallick
Salik Mallick 2020 年 10 月 7 日
Hello Mr.Belwal,
I meant why does ao have pi in it? I did the hand calculation and there shouldn't be a pi for the DC coefficent.
Star Strider
Star Strider 2020 年 10 月 11 日
See also an apparent duplicate: Fourier Series of Rectified Cosine Function

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Utkarsh Belwal
Utkarsh Belwal 2020 年 10 月 8 日
編集済み: Utkarsh Belwal 2020 年 10 月 8 日
Hello Salik,
You are right, there should be no pi in the DC coefficient and the value should be 3.5. According to me as a0 is a symbolic variable so it has the pi symbol included in it for better precision. I calculated the value of a0 that MATLAB is displaying, and it is coming 3.5. If you want to use the numeric value, then you can do a symbolic to numeric conversion as follows:
A0_numeric = double(a0);
DISCLAIMER: These are my own views and in no way depict those of MathWorks.
  1 件のコメント
Salik Mallick
Salik Mallick 2020 年 10 月 10 日
Hello Mr. Belwal,
Would you know why this script isn't running?
%% Problem 17.9
display('Problem 17.9')
% Determine the Fourier coefficients an and bn of the
% first three harmonic terms of the rectified cosine
% wave
syms n t
T = 8;
Wo=2*pi/T;
n = 1:3;
an = (2/T)*[int(2.5*cos(n*Wo*t)*cos(n*Wo*t),-2,2)]
AN_numeric = double(an)

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