LSTM Sequence to Sequence Regression Array Type Problem

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Ji Hyeon Cho
Ji Hyeon Cho 2020 年 10 月 4 日
コメント済み: Ji Hyeon Cho 2021 年 1 月 13 日
Hello, I am studying LSTM Sequence to Sequence Time Series Regression for Indoor Environmental.
When I read MATLAB Documentation for "trainNetwork", I had a problem about array type
following is the MATLAB Documentation text
----
net = trainNetwork(sequences,Y,layers,options) trains a recurrent network (for example, an LSTM or GRU network) for the sequence data specified by sequences and responses specified by Y.
(about Sequence)
Sequence or time series data, specified as an N-by-1 cell array of numeric arrays, where N is the number of observations, or a numeric array representing a single sequence.
For cell array or numeric array input, the dimensions of the numeric arrays containing the sequences depend on the type of data.
(about Y)
N-by-1 cell array of numeric sequences, where N is the number of sequences. The sequences are matrices with R rows, where R is the number of responses. Each sequence must have the same number of time steps as the corresponding predictor sequence.
For sequence-to-sequence regression tasks with one observation, sequences can be a matrix. In this case, Y must be a matrix of responses.
----
The Problems are
  1. if my Input data(Array X) has multiple input variable(x1, x2, x3 ,... xn) for Single Response y, Must I change my X's Type to cell?
  2. I had tried MATLAB Example, but I didn't understand diffrences in 2 case(Mat to Mat, Cell to Cell)
thank you!
  1 件のコメント
Ji Hyeon Cho
Ji Hyeon Cho 2020 年 10 月 4 日
X1 = linspace(1,100,100);
X2 = linspace(100,199,100);
X3 = linspace(200,299,100);
Y = linspace(300,399,100);
X1 = (X1 - min(X1)) / (max(X1)-min(X1));
X2 = (X2 - min(X2)) / (max(X2)-min(X2));
X3 = (X3 - min(X3)) / (max(X3)-min(X3));
X_MAT = [X1;X2;X3];
X_Cell = con2seq(X_MAT,100);
Y_MAT = Y;
Y_Cell = con2seq(Y,100);
numFeatures = 3;
numResponses = 1;
numHiddenUnits = 400;
layers = [ ...
sequenceInputLayer(numFeatures)
lstmLayer(numHiddenUnits)
fullyConnectedLayer(numResponses)
regressionLayer];
options = trainingOptions('adam', ...
'MaxEpochs',100, ...
'GradientThreshold',1, ...
'InitialLearnRate',0.5, ...
'LearnRateSchedule','piecewise', ...
'LearnRateDropPeriod',125, ...
'LearnRateDropFactor',0.2, ...
'Verbose',1, ...
'Plots','training-progress');
net_Mat = trainNetwork(X_MAT,Y_MAT,layers,options);
net_Cell = trainNetwork(X_Cell,Y_Cell,layers,options);
for i = 1: 100
[net_Mat,YpredMat(:,i)] = predictAndUpdateState(net_Mat,X_MAT(:,i));
end
for i = 1: 100
[net_Cell,YpredCell(:,i)] = predictAndUpdateState(net_Cell,X_Cell(:,i));
end
CVRMSE_MAT = sqrt(abs(mean(YpredMat.^2-Y_MAT.^2)))/mean(Y_MAT) * 100;
YpredCell = cell2mat(YpredCell);
Y_Cell = cell2mat(Y_Cell);
CVRMSE_Cell = sqrt(abs(mean(YpredCell.^2-Y_Cell.^2)))/mean(Y_Cell) * 100;

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採用された回答

Divya Gaddipati
Divya Gaddipati 2020 年 12 月 29 日
Hi,
I suggest you check the examples on sequence-to-sequence regression that are available in the documentation. Here's the link:
To answer your questions:
No. It doesn't necessarily have to be in cell format. In the case where your input data has sequences of different length, then you should be having the data in cells. As matrix doesn't support sequences of different lengths.
  1 件のコメント
Ji Hyeon Cho
Ji Hyeon Cho 2021 年 1 月 13 日
Thank you Divya!
Your answer is so helpful!

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