answer to a quadratic function

9 ビュー (過去 30 日間)
Agatha E. Johnson
Agatha E. Johnson 2020 年 9 月 30 日
コメント済み: Matt J 2020 年 9 月 30 日
Hi
how do I get both of my solution in a quadratic function? I only have the answer for x1

回答 (1 件)

Matt J
Matt J 2020 年 9 月 30 日
For example,
>> roots([1,5,2]) %roots of x^2+5*x+2
ans =
-4.5616
-0.4384
  2 件のコメント
Agatha E. Johnson
Agatha E. Johnson 2020 年 9 月 30 日
Hm, thanks for the answer. But when I do that the answer is not right.
this is the function, and how i didi it
  1. y = x^2+ x 12,
function [x1, x2] = myquadratic(a,b,c)
a = 1;
b = 1;
c = -12;
X = sqrt(b^2-4*a*c);
Y = 2*a;
x1 = (-b + X) / Y;
x2 = (-b - X) / Y;
here I only get
ans= 3
but i would like to get
ans=-4 as well
Matt J
Matt J 2020 年 9 月 30 日
In all likelihood, that is because you did not call the function with 2 output arguments.
K>> [x1,x2]=myquadratic()
x1 =
3
x2 =
-4

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeQuadratic Programming and Cone Programming についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by