i want to write code for a question

c=0.1(x-y)
x=4:0.01:12
y=sqrt(c/2)

i have to find the value of x for which c=.0038416

Answer 1

[Ameer Hamza]

Although this equation is linear is x, and you can write the equation of x. For a general case, you can use fsolve()

c = 0.0038416;

f = @(x) c - 0.1*(x-sqrt(c/2));
x = fsolve(f, 0);

If you have the symbolic toolbox

syms x

c = 0.0038416;

eq = c == 0.1*(x-sqrt(c/2));
x = double(solve(eq))

[Walter Roberson]

I think you missed the sqrt() in the symbolic part?

[Ameer Hamza]

Thanks for pointing out. OP kept changing the question initially, so I forgot to make the change in the symbolic part.