replace first match with a value,second match with a different value etc
古いコメントを表示
I have a txt with 2000 lines.In this txt EE1 appears 100 times.If i want to change the first EE1 i found with a value from a matrix (100,1) the second EE1 i found with the second value from the same matrix (100,1) and the third EE1 i found with the third value from the same matrix (100,1) ,etc ,how can i do it?
This follow code is a mix from something i found and the help of Jan Simon. It replaces only the first EE1 in the txt.
close all; clear; clc % Set user specific paths and values % ====================================================================== HFSS_EXE_PATH='C:\Program Files (x86)\Ansoft\HFSS12'; SCRIPT_PATH='c:\HFSS\scriptttt.vbs'; NEW_VBS_FILE='c:\HFSS\scrip.vbs'; % ======================================================================
for wg_y=6:1:8
% Replace first occurrence of ΕΕ1
fid1=fopen(SCRIPT_PATH,'r+');
vbs_str=fscanf(fid1,'%c');
old_str=('Array("NAME:XSize", "Value:=", "EE1"');
new_str=sprintf('Array("NAME:XSize", "Value:=", "%1.0fmm")',wg_y);
index = strfind(vbs_str, old_str);
new_vbs_str = [vbs_str(1:index(1) - 1), new_str, vbs_str(index(1) + length(old_str):end)];
% Create updated VB script file
fid=fopen(NEW_VBS_FILE,'w'); fprintf(fid,'%s',new_vbs_str); fclose(fid);
end
回答 (3 件)
Here is a funny one-liner for you, that could be adapted to your needs:
>> str = 'abc EE1 d EE1 00EE100' ; % Dummy example.
>> num = [10, 20, 34] ;
>> sprintf(regexprep(str, 'EE1', '%1.0fmm'), num)
ans = abc 10mm d 20mm 0034mm00
.. but you would have to tell us a bit more about the nature of your "numbers". Is this format '%1.0f' the one that you need, and do you also need to add 'mm' ?
EDIT: just to be clear, if the 100 occurrences of EE1 belong to the same file and your 100 numeric values are stored in a vector called wg_y, your code should be something like that:
fid = fopen(SCRIPT_PATH, 'r+') ;
vbs_str = fscanf(fid, '%c') ;
fclose(fid) ;
new_vbs_str = sprintf(regexprep(vbs_str, 'EE1', '%1.0fmm'), wg_y) ;
fid = fopen(NEW_VBS_FILE, 'w') ;
fprintf(fid, '%s', new_vbs_str) ;
fclose(fid) ;
Cheers,
Cedric
7 件のコメント
Cedric
2013 年 1 月 22 日
Ok, I modified my example accordingly. Also see Julian answer; if your replacements were strings directly, his answer would be the most efficient.
Cedric
2013 年 1 月 22 日
Re-edited after you posted the file.
Andrew
2013 年 1 月 22 日
Cedric
2013 年 1 月 22 日
If A is a vector, you would just replace wg_y with A actually. We can go on interacting through the forum or you can email your script to me (if you do so, send the text file as well).
Andrew
2013 年 1 月 22 日
Jan
2013 年 1 月 22 日
@Andrew: You have asked before you sent data by mail. I really appreciate this. Some other users think, that their problem is more important than the spare time of the ones they want a solution from.
Jan
2013 年 1 月 22 日
Equivalent to regexprep:
ResultString = sprintf(strrep(OriginalString, 'EE1', '%1.0fmm'), Value)
1 件のコメント
Cedric
2013 年 1 月 24 日
Actually, as I had never really used strrep (I might be too regexp-addicted for that ;-)), I just looked at the doc. now that I read your answer, and saw that strrep has an interesting behavior with overlapping occurrences of the pattern. Certainly something that I should keep in mind!
>> strrep( 'AAA', 'AA', 'Hello' )
ans = HelloHello
>> regexprep( 'AAA', 'AA', 'Hello' )
ans = HelloA
Julian
2013 年 1 月 22 日
Did you consider using regular expressions, e.g.
regexprep('some text ee1 some more text ee1 ee1', 'ee1', {'FIRST' 'SECOND' 'THIRD'}, 'once')
ans =
some text FIRST some more text SECOND THIRD
カテゴリ
ヘルプ センター および File Exchange で Programming についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!