recursive function to check a Palindrome

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Urmish Haribhakti
Urmish Haribhakti 2020 年 9 月 10 日
回答済み: xin yi leow 2021 年 1 月 25 日
function out=palindrome(x)
if n==1
Can anyone continue from here?

回答 (4 件)

John D'Errico
John D'Errico 2020 年 9 月 11 日
Why not try? I won't write it for you, as the entire problem is to make you think. I'll give you one hint, and I will hope nobody does the rest of your homework for you.
A vector is a palindrome if the first and last elements are the same, AND...
.... what else? That is, what information do you need about the rest of the vector? Is there some way you can treat this in a recursive way?
This is your homework, not ours, remember.
  1 件のコメント
Harsh Mittal
Harsh Mittal 2020 年 10 月 20 日
I tried writing the code but i am getting error as "MATLAB:TooManyOutputs" , can anyone help me resolve this error, i recieved this error while submiting my code


xin yi leow
xin yi leow 2021 年 1 月 25 日
function t=palindrome(char)
if length(char)==2
if char(1)==char(2)
elseif length(char)==1
if char(1)==char(end)

Johannes Hougaard
Johannes Hougaard 2020 年 9 月 10 日
There is no need to make it recursive or to look for multiple numel's
function out = palindrom(x)
x = upper(char(varargin{1})); % to account for inputs being UPPER/lower case and/or a string rather than a char
n = length(x);
iseven = rem(n,2) == 0;
middle = ceil(n/2);
if ~iseven
out = all(x(1:middle) == fliplr(x(middle:end)));
out = all(x(1:middle) == fliplr(x(middle+1:end)));
  4 件のコメント
Selvakumar T
Selvakumar T 2020 年 9 月 25 日
function Result = palindrome(t) if length(t) <= 1 Result= true; else Result= (t(1) == t(end) &&palindrome(txt(2:end-1))); end end


Wai Han
Wai Han 2020 年 10 月 18 日
編集済み: Wai Han 2020 年 10 月 18 日
Hello Urmish Haribhakti,
I suggest you to try your best like John D'Errico said.
But somehow, I can help you out by telling you the concept, (maybe a pseudocode).
% The input is a string which is in term a char array.
% Firstly, if the length of the string is 1, or isempty!! then the function should return logical 1 (true).
% elseif length ~= 1,check the first and last value of the vector,
% if first == last
% recall the function by removing those two values. for example, vector(2:end-1)
% Lastly, if the first and last value are not equal, the your output should be logical 0 (false).
I hope this can help you out!

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