find the minimum value of y for positive vales of x
2 ビュー (過去 30 日間)
古いコメントを表示
i have xmin=min(y(x>0)); where x=[-100:100] & y =x^3+60x^2-50 it gives me -50 which is wrong
aloso i have xmin=min(y(0:x(end))); where x=[-100:100] & y =x^3+60x^2-50 it gives me -50 which is wrong answer
any ideas? is my expression wrong ?
採用された回答
per isakson
2020 年 9 月 3 日
Try this
%%
x = (-100:100);
y = x.^3+60*(x.^2)-50;
%%
xmin = min(y(x>0))
which returns
xmin =
11
>>
0 件のコメント
その他の回答 (0 件)
参考
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!