Dealing with Character arrays

Hello everyone!
I have 3 (Date, Time, Pred) one-column character arrays and i want to create a new array with 3 columns. 1st column ---> Date, 2nd column ---> Time and 3rd Column ---> Pred. but i can't figure how to do that. Can anyone help me?
Thanks in advance,
Giorgos

 採用された回答

José-Luis
José-Luis 2013 年 1 月 10 日

0 投票

You probably need a cell array, especially if all the strings are not guaranteed to be of the same size.
col1 = char(reshape(32:127, 32, 3)'); %Some character array
col2 = col1;
col3 = col2;
%What you could use
your_cell_array = [cellstr(col1),cellstr(col2),cellstr(col3)];

その他の回答 (2 件)

Jan
Jan 2013 年 1 月 10 日
編集済み: Jan 2013 年 1 月 10 日

0 投票

So you have this, to mention it explicitly:
a = ['1'; '2'; '3'];
b = ['A'; 'C'; 'X'];
c = ['Q', '_', 'v'];
And these values represent Date, Time and Pred? Don't you think, that this is a very short representation? My guess is, that you do not have three [nx1] CHAR vectors. Anyhow, the solution would be:
R = [a,b,c]
Or equivalent:
R = cat(2, a, b, c);
If this is helpful, I strongly recommend to read the Getting Started chapters of the documentation, where such fundamental basics are explained.
Giorgos
Giorgos 2013 年 1 月 13 日
編集済み: Giorgos 2013 年 1 月 13 日

0 投票

Thanks for your time guys. José's answer was what i was looking for.

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