Find optimum value to fit with the answer
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Hi all,
I would like to know how to find an optimium value to reach or fit with the final result even if I change other variables as shown:
clear all;
clc;
x=10; y=20;
k=x+y;
f=20; m=10;
t=1; % I need to find the optimum value of t which should be in this case 41
final=k+f+m+t
if final<100
disp('ok')
else
disp('no')
end
2 件のコメント
Alan Stevens
2020 年 8 月 25 日
編集済み: Alan Stevens
2020 年 8 月 25 日
In the case you show, if t is 41 then final would be 101, which seems to exceed your desired value of 100.
Rik
2020 年 8 月 25 日
Don't use clear all. It clears all functions that were loaded to memory, which causes everything to be slower. If you want to clear the variables in a debugging context you can use clear or clearvars. Outside of debugging you should use functions to keep your workspace clean.
採用された回答
esat gulhan
2020 年 8 月 25 日
編集済み: esat gulhan
2020 年 8 月 25 日
Can it be like this, if you want to find value if final>100
clc;clear;
syms x y t k f m
x=10; y=20;
k=x+y;
f=20; m=10;
final=k+f+m+t>=100
t=solve(final,t)
of if you want to find value if final=100
clc;clear;
syms x y t k f m
x=10; y=20;
k=x+y;
f=20; m=10;
final=k+f+m+t==100
t=solve(final,t)
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