How can write loop for this algorithm?
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If i have A={1 1 2 2 3 3 3 4 4 8 9 10}
How can i run data from 1
after that i plus that data with 1
if data that i got is in A it will plus 1
if i not it will stop loop and show that outcome too
from my example it will stop at 4 and show 4 as a outcome
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回答 (1 件)
Jan
2020 年 8 月 25 日
編集済み: Jan
2020 年 8 月 25 日
I'm not sure, because the question is not completely clear to me. Perhaps:
A = [1 1 2 2 3 3 3 4 4 8 9 10];
d = diff(A);
v = find(d > 1, 1, 'first');
if isempty(v)
disp('Number not found')
else
A(v)
end
2 件のコメント
Jan
2020 年 8 月 30 日
What exactly is "the previous data"? Please explain explicitly, which output you want.
A = [-0.8687 -0.8677 -0.8677 -0.8667 -0.2547]
d = diff(A);
% d = [0.0010 0 0.0010 0.6120]
So do you search for the first number, which is greater than 0.001? Then use the already suggested code.
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