フィルターのクリア

How to calculate max multiplication possibility of three adjacent numbers in 10*10 matrix?

5 ビュー (過去 30 日間)
I have a matrix of 10 to 10 size of random digits from 0 to 9. How to calculate possible max multiplication of three adjacent numbers in matrix? I would like to consider only vertical and horizontal adjacent numbers, not diagonal.
r = randi([0 9],10,10);

採用された回答

Bruno Luong
Bruno Luong 2020 年 8 月 17 日
% Test matrix
A=randi([0 9],10,10)
B=cat(3,movprod(A,3,1),movprod(A,3,2));
[maxB,imax]=max(B,[],'all','linear');
[i,j,k]=ind2sub(size(B),imax);
if k==1
i=max(i-1,1):min(i+1,size(A,1));
j=j+zeros(size(i));
else
j=max(j-1,1):min(j+1,size(A,2));
i=i+zeros(size(j));
end
ilin = sub2ind(size(B),i,j);
% Display the adjadcent elements
fm1 = repmat('A(%d,%d)*', 1, length(i));
fm1(end) = [];
fm2 = repmat('%d*', 1, length(i));
fm2(end) = [];
fprintf(['%d = ' fm1 ' = ' fm2, '\n'], maxB, [i(:) j(:)]', A(ilin));
  3 件のコメント
Bruno Luong
Bruno Luong 2020 年 8 月 17 日
The size of the array is in the first line
A=randi([0 9],10,10)
The length of the adjacent elements are in the second arguments of MOVPROD in the second statement
B=cat(3,movprod(A,3,1),movprod(A,3,2));

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2020 年 8 月 17 日
conv2(A, ones(1,n), 'same')
and same with ones(n, 1)
take max() over all of it.

カテゴリ

Help Center および File ExchangeResizing and Reshaping Matrices についてさらに検索

製品


リリース

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by