plot curves in matlab
古いコメントを表示
Hi. How can i plot below equation(qa vs w)?
thank you
(9*w^4*cos(qa))/28000000 - (33*w^2*cos(qa))/32000 - (105*cos(qa))/64 + (603*w^2)/2560000 - (4891*w^4)/4480000000 + (93*w^6)/560000000000 + 105/64=0
回答 (2 件)
John D'Errico
2020 年 8 月 15 日
編集済み: John D'Errico
2020 年 8 月 15 日
fun = @(w,qa) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 + (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(fun)

You can tell fimplicit how far out to go of course.
fimplicit(fun,[-100 100 -100 100])

It does appear as if much is happening when you broaden the view.
2 件のコメント
saman ahmadi
2020 年 8 月 15 日
John D'Errico
2020 年 8 月 15 日
編集済み: John D'Errico
2020 年 8 月 15 日
Sigh. It would have helped if you asked that question in the first place, instead of just asking how to plot qa as a function of w.
fun = @(qa,w) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 + (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(fun,[-pi pi 0 100])
If you are looking for a specific result, then you need to tell people. That seems to come pretty close, though the scaling of the variables seems to be different from the plot you show. That is more a question of the specific function you gave us, which is surely different from that which generated your plot.

Alan Stevens
2020 年 8 月 15 日
Somethig like this:
qafn = @(w) acos(( 4891*w.^4/4480000000 -93*w.^6/560000000000 -603*w.^2/2560000 -105/64 )...
./(9*w.^4/28000000 - 33*w.^2/32000 - 105/64 ));
w = -50:50;
qa = qafn(w);
plot(w,qa)
6 件のコメント
saman ahmadi
2020 年 8 月 15 日
Alan Stevens
2020 年 8 月 15 日
編集済み: Alan Stevens
2020 年 8 月 15 日
So change the plotting range from -pi to pi in steps of pi/100, say, i.e. replace
w = -50:50;
with
w = -pi:pi/100:pi;
saman ahmadi
2020 年 8 月 15 日
Alan Stevens
2020 年 8 月 15 日
Oops! I've inverted everything!
Alan Stevens
2020 年 8 月 15 日
編集済み: Alan Stevens
2020 年 8 月 15 日
Looks like the implicit function is the way to go, though the w axis is scaled differently.
qawfn = @(qa,w) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 ...
+ (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(qawfn,[-pi pi 0 90])

saman ahmadi
2020 年 8 月 15 日
カテゴリ
ヘルプ センター および File Exchange で Vehicle Scenarios についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!