Info
この質問は閉じられています。 編集または回答するには再度開いてください。
Unusual size of array
1 回表示 (過去 30 日間)
古いコメントを表示
close all;
clc;
clear;
sobj=sparameters('W=2um_L=20um.s2p');
s=sobj.Parameters;
freq=sobj.Frequencies;
y_params = s2y(s);
y11=y_params(1,1,:);
y12=y_params(1,2,:);
y21=y_params(2,1,:);
y22=y_params(2,2,:);
Ca=(imag(y11+y12))./(2*pi.*freq);
Cb=(imag(y22+y21))./(2*pi.*freq);
R=real(-1/y21);
L=(imag(-1/y21))./(4*pi*freq);
In the code above I converted S parameter in s2p file attached to y parameters, and I am trying to to calculate some values from that. However for some reason the size of Ca, Cb and L arrays is unusual, according to me they should be 1D arrays with 201 values, however when calculated they come out to be 201X201 values.
Can someone point out the mistake in my code? I am very new to this, any optimisation and use of objects and how I am accesing y parameters, any improvement will be highly appreciated.
Thankyou in advance.
2 件のコメント
David Hill
2020 年 8 月 13 日
You just need to examine the sizes of your arrays in your workspace. I suspect that freq matrix is a 201x201. Not sure how you want to handle it.
R=real(-1./y21);%I believe you need ./
L=(imag(-1./y21))./(4*pi*freq);%same here
回答 (1 件)
Bruno Luong
2020 年 8 月 17 日
Try this
sobj=sparameters('W=2um_L=20um.s2p');
s=sobj.Parameters;
freq=sobj.Frequencies;
y_params = s2y(s);
y11=y_params(1,1,:);
y12=y_params(1,2,:);
y21=y_params(2,1,:);
y22=y_params(2,2,:);
Ca=(imag(y11(:)+y12(:)))./(2*pi.*freq(:));
Cb=(imag(y22(:)+y21(:)))./(2*pi.*freq(:));
R=real(-1./y21(:));
L=(imag(-1./y21(:)))./(4*pi*freq(:));
0 件のコメント
この質問は閉じられています。
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!