Count the number of occurances of an element using accumarray
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Now I am trying to find the occurance of an element in a vector using
sum(dta(:,size(dta,2))==3);
How can accumarray be used to find the frequency of elements ?
A = [7 11 2 3 4 5 4 7 7 2 1 4 1];
How can I get a result such as,
- 7 3
- 11 1
- 2 2
- 3 1
- 4 2
and so on.
Thanks in Advance.
P.S: I looked through other threads, but did not understand how it worked. The example given was count = accumarray(A',1) and the result was a vector which was not clear to me.
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Azzi Abdelmalek
2012 年 12 月 27 日
編集済み: Azzi Abdelmalek
2012 年 12 月 27 日
A = [7 11 2 3 4 5 4 7 7 2 1 4 1]
[a,b,c ]=unique(A,'stable')
out=[a' accumarray(c,1)]
3 件のコメント
Azzi Abdelmalek
2013 年 1 月 12 日
A = [7 11 2 3 4 5 4 7 7 2 1 4 1]
[a,b,c ]=unique(A) % you can remove 'stable'
% a is the array containing unique value but in sorted order
%a=[ 1 2 3 4 5 7 11], if you remove 'stable', the result will be sorted
%c=[6 7 2 3 4 5 4 6 6 2 1 4 1] gives the indices of each value of A in a
% for example the 2nd value 11 in A is the 7nth in a
out=[a' accumarray(c,1)], %the result is sorted
1 2
2 2
3 1
4 3
5 1
7 3
11 1
その他の回答 (1 件)
Sean de Wolski
2012 年 12 月 27 日
I would use histc on the output vector c that you have above from unique()
Frankly you should be able to skip all of that altogether:
[uv, idx] = unique(A);
n = histc(A,uv);
nA = n(idx)
(not tested in ML)
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