Draw 3 D from 4 data sets

How I can draw 3 D from the these data to get graph as atteched?
x1 = [60 65 70 75 80 85 90 95]
y 1= [717.7443511 450.2110549 315.3203173 281.0355881 310.2619146 367.5904781 425.4810863 466.5103523]
x2 = [32 34 36 38 40 42 44]
y2 = [2461.769179 2698.95206 2893.41954 2863.069124 2539.331353 1964.921629 1246.066407]

4 件のコメント

KSSV
KSSV 2020 年 8 月 4 日
With the given data it is not possible to get the plots shown as attached.
Cris LaPierre
Cris LaPierre 2020 年 8 月 4 日
You either need to pick 3 of the 4, or provide an equation for Z based on the values of X and Y.
Consider taking a look at some of the examples on the documentation page for surf.
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 4 日
Thank you for your replies
what about these data?
LL = [50.0 60.0 70.0 80.0 90.0 100.0 110.0]
UCS = [2695.6 1417.5 671.1 403.6 412.6 510.3 621.1]
PL = [15.0 20.0 25.0 30.0 35.0 40.0 45.0]
UCS = [9467.7 5552.5 2276.9 535.1 476.1 671.1 128.2 ]
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 4 日
I dont have equation for z
The values i got them from tests on soil

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回答 (1 件)

Ghufran Aldawood
Ghufran Aldawood 2020 年 8 月 4 日

0 投票

The data sets that you have don't have the same dimensions, if you have the same dimension on all sets, I assume you want to use the fourth set for color gradient. For that you can use the patch function in Matlab. I've attached code and figures.

9 件のコメント

Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 4 日
Ghufran Aldawood thank you
I've tried the code but I coudnt apply the data
if possoble, I need the UCS values to be in z axis
below are new data with same demintions
LL = [50.0 60.0 70.0 80.0 90.0 100.0 110.0]
UCS = [2695.6 1417.5 671.1 403.6 412.6 510.3 621.1]
PL = [15.0 20.0 25.0 30.0 35.0 40.0 45.0]
UCS = [9467.7 5552.5 2276.9 535.1 476.1 671.1 128.2 ]
Ghufran Aldawood
Ghufran Aldawood 2020 年 8 月 5 日
PL = [15.0 20.0 25.0 30.0 35.0 40.0 45.0];
UCS = [9467.7 5552.5 2276.9 535.1 476.1 671.1 128.2];
LL = [50.0 60.0 70.0 80.0 90.0 100.0 110.0];
figure(1)
stem3(PL, UCS, LL)
grid on
PL2 = linspace(min(PL), max(PL), 20);
UCS2 = linspace(min(UCS), max(UCS), 20);
[X,Y] = meshgrid(PL2, UCS2);
Z = griddata(PL,UCS,LL,X,Y);
figure(2)
surf(X, Y, Z);
grid on
set(gca, 'ZLim',[0 100])
shading interp
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 5 日
Thank you for your help.
In your code you just include one UCS where for each LL there is UCS value
the same for PL. is there what make the UCS values to be in z axis?
LL1 = [50.0 60.0 70.0 80.0 90.0 100.0 110.0]
UCS 1 = [2695.6 1417.5 671.1 403.6 412.6 510.3 621.1]
PL 2 = [15.0 20.0 25.0 30.0 35.0 40.0 45.0]
UCS 2 = [9467.7 5552.5 2276.9 535.1 476.1 671.1 128.2 ]
Ghufran Aldawood
Ghufran Aldawood 2020 年 8 月 6 日
You can't graph in 3D with 4 data sets.
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 6 日
Thank you I thought it is possible where I have 3 variables LL,PL, UCS But with different values for ucs
Ghufran Aldawood
Ghufran Aldawood 2020 年 8 月 6 日
You have UCS 1 which is one variable, and UCS 2 which is a second variable. It does not matter that they have the same name. For example, here are 3 variables:
X1 = 1,5,10,15,20
X2 = 1,2,3,4,5
X3 = 2,4,6,8,10
The figure:
The code:
X1 = [1 5 10 15 20];
X2 = [1 2 3 4 5];
X3 = [2 4 6 8 10];
plot3(X1,X2,X3);
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 6 日
It’s helpful Thank you
Ghufran Aldawood
Ghufran Aldawood 2020 年 8 月 6 日
Glad I can help. Good luck!
Asma A Bder Muhmed
Asma A Bder Muhmed 2020 年 8 月 6 日
You too

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