# How to check if my time series has a repeated hour in a matrix of 10200 rows?

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Fabian Moreno 2020 年 7 月 28 日
コメント済み: Fabian Moreno 2020 年 7 月 29 日
Hello, I have this time series matrix from 01/01/2019 to 29/02/2020, hourly. I would like to know if in some part of the matrix the hour or the day, is repeated with respect to the previous row? I appreciate if anyone knows how I can find that, Thank you.
Var 1 yy mm dd hh min
737426 2019 1 1 0 0
737426.041666667 2019 1 1 1 0
737426.083333333 2019 1 1 2 0
737426.125000000 2019 1 1 3 0
737426.166666667 2019 1 1 4 0
737426.208333333 2019 1 1 5 0
737426.250000000 2019 1 1 6 0
737426.291666667 2019 1 1 7 0
737426.333333333 2019 1 1 8 0
737426.375000000 2019 1 1 9 0
737426.416666667 2019 1 1 10 0
737426.458333333 2019 1 1 11 0
737426.500000000 2019 1 1 12 0
737426.541666667 2019 1 1 13 0
737426.583333333 2019 1 1 14 0
737426.625000000 2019 1 1 15 0
737426.666666667 2019 1 1 16 0
737426.708333333 2019 1 1 17 0
737426.750000000 2019 1 1 18 0
737426.791666667 2019 1 1 19 0
737426.833333333 2019 1 1 20 0
737426.875000000 2019 1 1 21 0
737426.916666667 2019 1 1 22 0
737426.958333333 2019 1 1 23 0
737427 2019 1 2 0 0
737427.041666667 2019 1 2 1 0
737427.083333333 2019 1 2 2 0
... Until February 2020

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### 採用された回答

jonas 2020 年 7 月 28 日
Convert everything to datetime and then check the difference
%some data, note that 2000-1-1 10:00:00 is repeated
t = datetime(2000,1,1,[0:10,10:100],0,0);
%find instances where the difference is smaller than 1h
id = find(diff(t) < hours(1))
id =
11
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Fabian Moreno 2020 年 7 月 29 日
thank you jonas, just to know, I use this one "id = find(diff(t) < hours(1))" abd worked pretty good, but instead of hours, there is another form to use to days or months, I did it with days and didn't work. Thank you

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