How to check if my time series has a repeated hour in a matrix of 10200 rows?

Hello, I have this time series matrix from 01/01/2019 to 29/02/2020, hourly. I would like to know if in some part of the matrix the hour or the day, is repeated with respect to the previous row? I appreciate if anyone knows how I can find that, Thank you.

Var 1 yy mm dd hh min

737426 2019 1 1 0 0

737426.041666667 2019 1 1 1 0

737426.083333333 2019 1 1 2 0

737426.125000000 2019 1 1 3 0

737426.166666667 2019 1 1 4 0

737426.208333333 2019 1 1 5 0

737426.250000000 2019 1 1 6 0

737426.291666667 2019 1 1 7 0

737426.333333333 2019 1 1 8 0

737426.375000000 2019 1 1 9 0

737426.416666667 2019 1 1 10 0

737426.458333333 2019 1 1 11 0

737426.500000000 2019 1 1 12 0

737426.541666667 2019 1 1 13 0

737426.583333333 2019 1 1 14 0

737426.625000000 2019 1 1 15 0

737426.666666667 2019 1 1 16 0

737426.708333333 2019 1 1 17 0

737426.750000000 2019 1 1 18 0

737426.791666667 2019 1 1 19 0

737426.833333333 2019 1 1 20 0

737426.875000000 2019 1 1 21 0

737426.916666667 2019 1 1 22 0

737426.958333333 2019 1 1 23 0

737427 2019 1 2 0 0

737427.041666667 2019 1 2 1 0

737427.083333333 2019 1 2 2 0

... Until February 2020

Answer 1

[jonas]

Convert everything to datetime and then check the difference

%some data, note that 2000-1-1 10:00:00 is repeated
t = datetime(2000,1,1,[0:10,10:100],0,0);

%find instances where the difference is smaller than 1h
id = find(diff(t) < hours(1))

id =

    11

[Fabian Moreno]

thank you jonas, just to know, I use this one "id = find(diff(t) < hours(1))" abd worked pretty good, but instead of hours, there is another form to use to days or months, I did it with days and didn't work. Thank you