Line 34 * unknown operator

Confused about why this doesnt work at the end. The arrays all have the correct dimensions. Any help would be appreciated.

A=3;

E=4;

I=5;

le=2;

thetae=[pi/2;pi/4;pi/6];

c=cos(thetae);

s=sin(thetae);

N=numel(thetae); %counts elements of thetae vector

T=cell(1,N);

keprime=cell(1,N); %makes empty celled matrix

for i=1:N

keprime{i}=[A*E/le,0,0,-A*E/le,0,0;

0,12*E*I/le^3,6*E*I/le^2,0,-12*E*I/le^3,6*E*I/le^2;

0,6*E*I/le^2,4*E*I/le,0,-6*E*I/le^2,2*E*I/le;

-A*E/le,0,0,A*E/le,0,0;

0,-12*E*I/le^3,-6*E*I/le^2,0,12*E*I/le^3,-6*E*I/le^2;

0,6*E*I/le^2,2*E*I/le,0,-6*E*I/le^2,4*E*I/le];

end

for i=1:N

T{i}=[c(i),s(i),0,0,0,0; %Transfer Matrix set translates global coordinates to local coordinates

-s(i),c(i),0,0,0,0;

0,0,1,0,0,0;

0,0,0,c(i),s(i),0;

0,0,0,-s(i),c(i),0;

0,0,0,0,0,1];

end

T1=T(1);

T2=T(2);

T3=T(3);

ke1=T1.'*keprime(1)*T1;

ke2=T2.'*keprime(2)*T2;

ke3=T3.'*keprime(3)*T3;

[madhan ravi]

Revived your question from the spam quarantine.

[JONATHAN DAVID JR FREEMAN]

Thanks!

Answer 1

[madhan ravi]

After the second loop use {} instead of () by the way those two loops can be reduced to one single loop.

[JONATHAN DAVID JR FREEMAN]

Thank you again. Great help!

[madhan ravi]

I don’t know why there is an exhaustive first loop , you don’t seem to change anything in each iteration. Simply repmat() tk replicate the elements.