How is parfor time taken is larger than that by normal for loop ?

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Nader Rihan
Nader Rihan 2020 年 7 月 17 日
回答済み: Sindar 2020 年 7 月 17 日
The time taken (t1) by parfor is larger than that (t2) by the normal for loop,I don't understand why ?

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回答 (1 件)

Sindar
Sindar 2020 年 7 月 17 日
Best guess: you don't preallocate y, nor clear it. So, the parfor needs to expand the vector constantly while the for is simply overwriting elements. Try
x=1:4000;
y1=false(size(x));
y2=false(size(x));
...
y1(i)=
...
y2(i)=

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