Converting 2D array to 3D array by sector

Hi all,
I have a question concerning reshaping a 2D array into a 3D array, where each 2D array is arranged by a block of rows and columns from the original.
Say I have an array 'aa'
'aa' is comprised of a number of blocks of data = x, with a number of rows = n, and number of columns = m
For example if
x = 2
n = 2
m = 3
aa = randi(1000,x*n,m);
Can anyone show me how to reshape 'aa' into a destination array 'bb' to be organized as follows
bb(:,:,1) = aa(1:n,:);
bb(:,:,2) = aa(n+1:2*n,:);
The same pattern repeats for the full size of my problem (x = 30 , n = 440, m =320)
I am trying to avoid loops as the number of blocks of data 'x' is likely to increase down the road.
Thank you in advance for any help that you may provide.
Chris

2 件のコメント

madhan ravi
madhan ravi 2020 年 7 月 14 日
Why did you edit after I answered??
Christopher
Christopher 2020 年 7 月 14 日
I was trying to make my question more clear and I didn't see your answer when I was editing it. I accepted it as correct, thanks again and sorry for the confusion on my part.

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 採用された回答

madhan ravi
madhan ravi 2020 年 7 月 14 日

0 投票

bb = reshape(aa.', 1, [], size(aa,2))

1 件のコメント

Christopher
Christopher 2020 年 7 月 14 日
This is exactly what I was looking for, thank you very much.

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