given that you have this line of code how do you count the number of points in each quadrant ?

1 回表示 (過去 30 日間)
Classical = pdist2(matrix_logdiff_nsample, mean(matrix_logdiff_nsample),'mahal');
p = size(matrix_logdiff_nsample,2);
chi2quantile = chi2inv(0.99,p);
[SFmcd, MFmcd, Fmcd, OutFmcd] = robustcov(matrix_logdiff_nsample);
plot(Classical, Fmcd, 'o')
line([chi2quantile, chi2quantile], [0, 120], 'color', 'r')
line([0, 80], [chi2quantile, chi2quantile], 'color', 'r')
hold on
plot(Classical(OutFmcd), Fmcd(OutFmcd), 'b*')
xlabel('Mahalanobis Distance')
ylabel('Robust Distance')
title('Distance Plot, Fast MCD method')
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採用された回答

Adam Danz
Adam Danz 2020 年 7 月 12 日
編集済み: Adam Danz 2020 年 7 月 13 日
You just need to modify either of the two answers received for similar questions in the past (listed under your question).
To modify this answer, you just need to replace the centerPoint_x, centerPoint_y values with the coordinates you're using to define the quadrants.
Based on your image it would look something like,
centerPoint_x = 15; % approximate guess based on image
centerPoint_y = 18; % approximate guess based on image
  5 件のコメント
Adam Danz
Adam Danz 2020 年 7 月 13 日
編集済み: Adam Danz 2020 年 7 月 15 日
You need to exchange "x" and "Y" with whatever values you're using to define the center point. Don't just copy-paste without doing the thinking.

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