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what does "parpool close force local" mean?

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zhu wenguo
zhu wenguo 2020 年 7 月 12 日
コメント済み: zhu wenguo 2020 年 7 月 12 日
I am using a code based on old version matlab, and I got a error when it comes to:
if numProc <= 1
parpool close force local
else
% poolSize = parpool('size'); % check to see if a pool is already open
p = gcp('nocreate'); % If no pool, do not create new one.
if isempty(p)
poolSize = 0;
else
poolSize = p.NumWorkers
end
if poolSize == 0 || poolSize < numProc || poolSize ~= numProc
parpool close force local
eval(['parpool open ' num2str(numProc)])
end
end
and got the following error:
Error using parpool (line 145)
Properties and values must be specified in pairs.
it seems that the command has been deprecated, what does it mean? and what is its alternatives?
thank you in advance!

採用された回答

Walter Roberson
Walter Roberson 2020 年 7 月 12 日
Something like,
if numProc <= 1
p = gcp('nocreate');
if ~isempty(p)
delete(p);
end
poolSize = 0;
else
p = gcp('nocreate');
if isempty(p)
poolSize = 0;
else
poolSize = p.NumWorkers;
if poolSize ~= numProc
delete(p);
poolSize = 0;
end
end
if poolSize == 0
try
p = parpool(numProc);
poolSize = p.NumWorkers;
catch
poolSize = 0;
end
end
end
  1 件のコメント
zhu wenguo
zhu wenguo 2020 年 7 月 12 日
Thank you very much! it works!

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