I found the solution, I didn't post the frequency of sampling. But apparently fftshift just swaps X axis and then if there were no 0 between samples they get joined. So I had to add zeroes to the fft result in order for the fftshift to work properly, this is by extending the sampled rate of the original function. (Making sampling frequency higher extends repeating time in frequency domain vice versa making sampled range larger adds samples to the frequency domain in between the existing samples.)
fftshift isn't workig
9 ビュー (過去 30 日間)
古いコメントを表示
Vitali Pomanitski
2020 年 7 月 8 日
回答済み: Vitali Pomanitski
2020 年 7 月 10 日
Hi,
I successfully got two deltas on 4/10 and on 2/10, but I cannot center the graph.
Could you help me?
t = 0:(1/fs):(10-1/fs);
S = 2*cos(3*pi*t/10).*cos(pi*t/10); %cos(4pit/10)+cos(2pit/10)
n = length(S);
X = fft(S);
f = (0:n-1)*(fs/n)*2; %multiply by pi*2, leave the pi aside
f80 = (0:n-1);
power = abs(X).^2/n;
stem(f,power)
Y = fftshift(X)
fshift = (-n/2:n/2-1)*(fs/n)
powershift = abs(Y).^2/n;
plot(fshift,powershift)
I attached pictures. In the second graph those are not even deltas.
0 件のコメント
採用された回答
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Fourier Analysis and Filtering についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!