signal fourier transform include unit step function
39 ビュー (過去 30 日間)
古いコメントを表示
hey there. the question is this : x(t) = (exp(1)^-t)×u(t) note: u(t) is unit step function that has valeu 1 for (t >= 0) question is calcutlating X(w) the main idea is that (t) is symbol but u(t) only changes the range of fourier integral.
my code :
syms t;
t = linspace(-20, 20, 5000);
u = @(t) (t >= 0);
x = @(t) exp(1).^(-t).*u(t);
x_w = fourier(x(t))
error : check for missing argument or incorrect argument data type in call to function 'fourier'
i found that I can't handle that unit step function in x(t). when i don't have u(t) so I don't need t = linspace...... then every thing works great. but i need to solve this question
0 件のコメント
採用された回答
Star Strider
2020 年 7 月 1 日
Try this version of your code:
syms t x(t)
% t = linspace(-20, 20, 5000);
% u = @(t) (t >= 0);
x(t) = exp(-t) * heaviside(t);
x_w = fourier(x(t))
producing:
x_w =
1/(1 + w*1i)
The parts I commented (%) are not necessary here.
.
4 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Calculus についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!