How to modify values in an array at a certain point inside a loop?

I have formed this simple code

clc
clear all
a=1.4
for i=1:10       %Here i represents years
    A(:,:,i)=a;  %For storing the values in 3D matrix
    a = a * 0.9;
end

The answer I am getting is

val(:,:,1) =

1.4000

val(:,:,2) =

1.2600

val(:,:,3) =

1.1340

val(:,:,4) =

1.0206

val(:,:,5) =

0.9185

val(:,:,6) =

0.8267

val(:,:,7) =

0.7440

val(:,:,8) =

0.6696

val(:,:,9) =

0.6027

val(:,:,10) =

0.5424

I want to modify my code such that when the value of 'a' becomes less than a<0.6*1.4 so for that year 'a' should be 1.4 again.Like in this case in year 6 the value is 0.8267 which is less than 0.6*1.4 so val(:,:,6) should become 1.4 and then again the 'a' will be calculated as per defined equation.I mean I want my answer like this and also I want the year in which the value becomes 1.4 again like here in this case the year is 6.How can I modify my code in order to get this answer?Kindly help me

Desired Answer:

val(:,:,1) =

1.4000

val(:,:,2) =

1.2600

val(:,:,3) =

1.1340

val(:,:,4) =

1.0206

val(:,:,5) =

0.9185

val(:,:,6) =

1.4000

val(:,:,7) =

1.2600

val(:,:,8) =

1.1340

val(:,:,9) =

1.0206

val(:,:,10) =

0.9185

Answer 1

[darova]

Just add if condition inside your for loop

clc
clear all
a=1.4
for i=1:10       %Here i represents years
    A(:,:,i)=a;  %For storing the values in 3D matrix
    a = a * 0.9;
    if a < 1.4*0.6
        a = 1.4;
    end
end

[Rabia Zulfiqar]

Thankyou so much for your help dear. Can you also please idntify that how would I know the year where this replcament has been done?

For instance I know that I can do something like this

b=find(A==1.4);
B=b(2);

and then B should be equal to 6 but is there any other way to find this year?

[darova]

You are doing ok, It's the right wayt to find the year. Why do you want another method?

The only thing: use some tolerance since you have float numbers

Find

ind = find(abs(A-1.4)<0.01);
B = b(ind);