Solving nonlinear ordinary differential equations

I want to solve the following equation:
h(x) = -(D+a*(D/RT)*o*C)dc/dx
% D, a, R,T, o are parameters
%Boundary conditions:
h(0,t)=h(w,t) = C_sat;
%Initial conditions:
c(x,0)=0;

12 件のコメント

darova
darova 2020 年 6 月 26 日
What about bvp4c?
bbah
bbah 2020 年 6 月 26 日
how would it look like for this equation ? i need for that a system of first order equations. How do i get that ?
bbah
bbah 2020 年 6 月 26 日
The equation is time indipendent actually. Sorry about that
Ameer Hamza
Ameer Hamza 2020 年 6 月 26 日
Do you just a single equation or multiple equations? What is h(x)? Can you attach the equations in mathematical form?
bbah
bbah 2020 年 6 月 28 日
Hello. This is the equation i want to solve. It is steady state so no time dependency is given and the parameters D,alpha, R,T and Omega are given.
The initial condition is:
and the boundary Conditions are: h(0,t) = h(w,t) = 1
darova
darova 2020 年 6 月 29 日
This is not ODE (ordinary diff equation), it's PDE (partial diff equation)
You have more than one (two) variables. YOu have two uknown functions (c and h). But i see only one equation? Where is the second one?
bbah
bbah 2020 年 6 月 29 日
that is why i am confused too. h should be the flux of the diffusion of c into a body and there is no second equation.
darova
darova 2020 年 6 月 29 日
One equation - one uknown function
bbah
bbah 2020 年 6 月 29 日
what if h = c/c^0 ?
darova
darova 2020 年 6 月 29 日
it means h = c (the same function)
bbah
bbah 2020 年 7 月 2 日
sorry for the later response. I think the final equation to be solved is this.
The flux needs to be implemented into the mass balance equation leading to this equation in 1D:
alpha, omega, D, R and T are known ant the boundary conditions are:
c(0,t)=c(w,t) = e.g. 1000 for t(0,t_end)
initial condition
c(x,0) = 0, for x(0,w);
i hope you can help me with this equation
darova
darova 2020 年 7 月 2 日
What about method of lines?

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