How can I predict the value of the coefficients?

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Atony Garcia
Atony Garcia 2020 年 6 月 26 日
編集済み: Image Analyst 2020 年 6 月 28 日
So I have this polynomial equation 𝑝(𝑥) = 𝑎 + 𝑎1𝑥 + 𝑎2𝑥^2 + 𝑎3𝑥^3 and it is cero when x = -2,1,3,4 and I need to answer with the values of the coefficients and proving that the answer is correct
I have tried this code but I am not sure if it is the right one:
p= [a a a a]
h =polyval([4 3 1 -2],0)
Thank you

回答 (2 件)

Walter Roberson
Walter Roberson 2020 年 6 月 26 日
Use polyfit() to compute p; the corresponding y would be 0.
You will probably think that the answer you get back from polyfit is incorrect, but it is correct under the condition that your cubic polynomial is zero at all four points x = -2,1,3,4
  3 件のコメント
Walter Roberson
Walter Roberson 2020 年 6 月 28 日
what is your code and what is the error?. your x is [-2,1,3,4] and your y is all zeros.
Atony Garcia
Atony Garcia 2020 年 6 月 28 日
Its the code I posted above in the first question

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Image Analyst
Image Analyst 2020 年 6 月 28 日
編集済み: Image Analyst 2020 年 6 月 28 日
If you already know A, try roots with your given a vector.
x = roots([a(4), a(3), a(2), a(1)])
You should find x is [-2,1,3,4] if what it said was true.
You could also compute a Lagrange interpolating polynomial
y = (x- -2)*(x-1)*(x-3)*(x-4)
then multiply that out to find out the coefficients. Note that if you have x=0 at 4 locations, you can't do that with a cubic - you need a 4th order equation.

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