no use of for loop
古いコメントを表示
Hi!
n=[0:0.01:0.5];
f=[2:0.01:3];
for k=1:length(n)
for l=1:length(f)
beta=n(k).*Dc/Dw
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
end
end
is there any advice to programm this without using for loops?
Thank you
EDIT CORRECTED PROGRAM:
Hi sorry. here is the corrected program.
n=[0:0.01:0.5];
f=[2:0.01:3];
epsilon_cc=2
for k=1:length(n)
for l=1:length(f)
beta=n(k);
omega=2e9*pi*f(l);
epsilon=3./(1+j*omega*tau);
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)*(epsilon_cc))
end
end
thank you for your help!
2 件のコメント
Azzi Abdelmalek
2012 年 11 月 29 日
What are sizes of Dc , omega
Wayne King
2012 年 11 月 29 日
You should make your post so that people can actually execute your code. You do not give Dc, or Dw, and what is this line
epsilon_k(k,l)=(beta*(epsilon)+(1-beta)(epsilon_cc));
are you multiplying 1-beta and epsilon_cc?
採用された回答
その他の回答 (0 件)
カテゴリ
ヘルプ センター および File Exchange で Loops and Conditional Statements についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!