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Continuing Matrix involving a function to make very large

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Seb apple
Seb apple 2020 年 6 月 17 日
回答済み: Ameer Hamza 2020 年 6 月 17 日
Hi all, i have a typed square matrix and need to expand it to be very large how ever this will take far too long to do manually. my matrix code is below please help if you know any function to expend it while keeping the same pattern.
thanks in advance
syms e P n
c=1;
G(n)=e/(2*(P+0.5*(1i*n*c)-(0.25*(n)^2)));
j=[1 0 G(7) 0 0 0 0 0 0 0 0 0 0 0 0;0 1 0 G(6) 0 0 0 0 0 0 0 0 0 0 0; G(5) 0 1 0 G(5) 0 0 0 0 0 0 0 0 0 0; 0 G(4) 0 1 0 G(4) 0 0 0 0 0 0 0 0 0; 0 0 G(3) 0 1 0 G(3) 0 0 0 0 0 0 0 0; 0 0 0 G(2) 0 1 0 G(2) 0 0 0 0 0 0 0; 0 0 0 0 G(1) 0 1 0 G(1) 0 0 0 0 0 0 ; 0 0 0 0 0 G(0) 0 1 0 G(0) 0 0 0 0 0; 0 0 0 0 0 0 G(-1) 0 1 0 G(-1) 0 0 0 0; 0 0 0 0 0 0 0 G(-2) 0 1 0 G(-2) 0 0 0; 0 0 0 0 0 0 0 0 G(-3) 0 1 0 G(-3) 0 0; 0 0 0 0 0 0 0 0 0 G(-4) 0 1 0 G(-4) 0; 0 0 0 0 0 0 0 0 0 0 G(-5) 0 1 0 G(-5); 0 0 0 0 0 0 0 0 0 0 0 G(-6) 0 1 0; 0 0 0 0 0 0 0 0 0 0 0 0 G(-7) 0 1 ];
  2 件のコメント
KSSV
KSSV 2020 年 6 月 17 日
'P' not defined.
KSSV
KSSV 2020 年 6 月 17 日
Read about diag.

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回答 (1 件)

Ameer Hamza
Ameer Hamza 2020 年 6 月 17 日
Try this
syms e o n
c=1;
P = 1;
G(n)=e./(2.*(P+0.5*(1i*n.*c)-(0.25*(n)^2)));
N = 15;
l_start = 5;
u_start = 7;
l_end = l_start-N+3;
u_end = u_start-N+3;
j = diag(ones(1,N)) + diag(G(l_start:-1:l_end), -2) + diag(G(u_start:-1:u_end), 2);

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