Boundaries points for Linear Programming (graphical)

i want to find these points without using intersection

9 件のコメント

Image Analyst
Image Analyst 2020 年 6 月 6 日
What data do you have to start with? You forgot to show your code for how you created this figure.
HMe
HMe 2020 年 6 月 6 日
this is the code i used
clear;clc
%Generate data
[H,C] = meshgrid(0:0.1:10);
NB=H+2*C;
% Get True where condition aplies, false where not.
cond1=-H+C<=3;
cond2=2*H+C<=28;
cond3=C<=8;
% Get boundaries of the condition
Cp1=3+H(1,:);
Cp2=28-2*H(1,:);
Cp3=8;
%Delete Areas whereCondition does not apply;
NB(~cond1)=NaN;
NB(~cond2)=NaN;
NB(~cond3)=NaN;
%% Plot
[C,h]=contourf(H,C,NB,20);
hold on
plot(H(1,:),Cp1,'r')
plot(H(1,:),Cp2,'k')
plot(H(1,:),ones(size(H(1,:))) * Cp3,'r')
axis([0 10 0 10])
xlabel('H, Hydropower')
ylabel('C, Crops')
KSSV
KSSV 2020 年 6 月 6 日
What exactly you want?
HMe
HMe 2020 年 6 月 6 日
編集済み: HMe 2020 年 6 月 6 日
i want to get the points in the graph with matlab code not using the Data cursour so i can resolve a maximization problem for linear programming
KSSV
KSSV 2020 年 6 月 6 日
You can use interpolation logics to get the points you want. Is that okay for you?
HMe
HMe 2020 年 6 月 6 日
what's interploation logics and how to use them ???
KSSV
KSSV 2020 年 6 月 6 日
For the give lines in the figure, if you get the intersection points is that enough?
HMe
HMe 2020 年 6 月 6 日
I thought about that but i'm looking for solution that works on every system
Alexandre Riebel
Alexandre Riebel 2020 年 7 月 24 日
編集済み: Alexandre Riebel 2020 年 7 月 24 日
It's not clear exaclty what you are looking for. For every situation that you are looking at, will there be a point at the origin, and will there be a point on the x-axis and y-axis? Or are you just looking for the intersection point between the black and red lines?

サインインしてコメントする。

回答 (1 件)

John D'Errico
John D'Errico 2020 年 7 月 24 日
編集済み: John D'Errico 2020 年 7 月 24 日

0 投票

You probably want to use the code plotregion, by Per Bergström. It can be found on the file exchange.
Of course, if you have a 4-d problem or greater, then nothing will work, at least to plot.
plotregion handles general sets of linear inequality constraints, as well as bound constraints. If you have equality constraints too, things will become more complex.
If your goal is to find the intersection points themselves, then a tool like this may be appropriate, thus the function LCON2VERT from this set of tools by Matt J.
As well, there are tools from Michael Kleder, which apparently inspired the tools from Matt.

カテゴリ

ヘルプ センター および File ExchangeComputational Geometry についてさらに検索

質問済み:

HMe
2020 年 6 月 6 日

編集済み:

2020 年 7 月 24 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by