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How to access elements of all field of structure in same loop

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Mekala balaji
Mekala balaji 2020 年 5 月 31 日
コメント済み: Stephen23 2020 年 5 月 31 日
Hi,
I defined structure and want to access elements of each feild. I use the below code and it giving error.
%%
close all
clear all
clc
student.name = 'Mekala';
student.age = 2;
student(2).name = 'Punith';
student(2).age = 6;
for i =1:length(student)
name{i} = student{i}.name
end
%% Error: Cell contents reference from a non-cell array object.
for i =1:length(student)
name(i) = student(i).name
end
%% Error: Subscripted assignment dimension mismatch.
for i =1:length(student)
age(i) = student(i).age
end
%% This works.
How to access the all field values in the same loop?

回答 (1 件)

Ameer Hamza
Ameer Hamza 2020 年 5 月 31 日
To access name filed, the following for-loop works
for i =1:length(student)
name{i} = student(i).name
end
However, for-loop is not needed, and there are other easy ways to create an array of all elements of the struct array. Try following code
student.name = 'Mekala';
student.age = 2;
student(2).name = 'Punith';
student(2).age = 6;
name = {student.name};
age = [student.age];
  2 件のコメント
Mekala balaji
Mekala balaji 2020 年 5 月 31 日
for loop is for a big structure, can't we access all the fields in same loop?
Ameer Hamza
Ameer Hamza 2020 年 5 月 31 日
Do you want to automatically create variables with the same name as fields in the structs? If yes, then such practice is highly non-recommended: https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval. I will create slow and buggy code. If you want to extract all the fields, then I suggest you continue to work with the struct, as the code will be much more efficient and easy to debug.

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