Sorting elements according to an array

I will try my best to phrase this question, hope it makes sense
I have 2 arrays, DATA which has useful data and SCALE which has the scale where I am fitting the data to.
DATA has numbers from 1-100 in random order, and SCALE has distinct intervals of tens from 1-100, i.e. 1,10,20,30...90,100
My goal is the write a code which clumps the elements from DATA to SCALE to do calulations such as SCALE-DATA (for example, 36 is the DATA element, the SCALE element should be 40 and it would be 40-36)
example - 7 will be rounded up to 10, and 23 will be rounded down to 20.
I understand the commands ciel and floor, however I am not sure what is the most efficient way to match the rounded data to the scale?

 採用された回答

Star Strider
Star Strider 2020 年 5 月 28 日

1 投票

I am not certain what you want.
Try this:
DATA = randi([1 100], 25, 1); % Create DATA
SCALE = 10*round(DATA/10).*(DATA>=10) + 10*round(DATA/10).*(DATA<10);
Out = [DATA, SCALE];
.

10 件のコメント

Hans123
Hans123 2020 年 5 月 29 日
編集済み: Hans123 2020 年 5 月 29 日
Hi StarStrider, thanks as always for the reply.
This is very close to what I want, but my scale is already pre-defined. and I want to match the rounded ones to the SCALE.
Your code creates the SCALE vector according to the DATA.
SCALE DATA
10 24~20 (goes to the second column)
20 ...
30 ...
40 ...
50 ...
Appreciate the help, as always!
Star Strider
Star Strider 2020 年 5 月 29 日
My pleasure!
I am still not certain that I understand what you want, so I will give it another shot:
Out = sortrows([SCALE DATA],1)
the rest of the code is unchanged.
I do not understand this: 24~20 or what you want to do with it. It is not likely that it will work as a single column in MATLAB.
Hans123
Hans123 2020 年 5 月 29 日
Thanks Star Strider, I am sorry for not being articulate enough. I believe in your code -
SCALE = 10*round(DATA/10).*(DATA>=10) + 10*round(DATA/10).*(DATA<10)
- makes the SCALE array according to the DATA array, however SCALE is predefined before the elements of DATA are introduced. Hope that helps sort it out.
Basically, DATA elements get rounded up or down to get close to an induvidual element of SCALE and gets sorted.
So there should be a line that says
SCALE = linspace(0,100,10);
Star Strider
Star Strider 2020 年 5 月 29 日
I am completely lost.
I will delete my Answer in a few minutes.
Hans123
Hans123 2020 年 5 月 29 日
編集済み: Hans123 2020 年 5 月 29 日
Oh wow, I am sorry Star Strider. Let me try to rephrase it again
Hans123
Hans123 2020 年 5 月 29 日
Again, since I lost my command of the English language.
I have points scattered on the x axis, and I want the points to rounded up to the nearest division.
Hans123
Hans123 2020 年 5 月 29 日
編集済み: Hans123 2020 年 5 月 29 日
Your code does exactly what I want, however the scale is defined from the data input. And with different data sets the scale changes. My scale is predefined and is indepenndent of the data set.
SCALE = 10*round(DATA/10).*(DATA>=10) + 10*round(DATA/10).*(DATA<10);
Something along the lines of this, but this is what I can't figure out
%predefined
DATA = [8 17 21 23 36]';
SCALE = [10 20 30 40]';
rounddata = round(DATA);
%compare with SCALE to see where it belongs and output
Out = [correctDATA, SCALE];
Star Strider
Star Strider 2020 年 5 月 29 日
Try this:
DATA = randi([1 100], 1, 25); % Create ‘DATA’
SCALEfcn = @(x) 10*round(x/10).*(x>=10) + 10*round(x/10).*(x<10);
SCALE = linspace(0,100,11);
for k = 1:numel(SCALE)-1
Out{k,:} = [SCALE(k) DATA((SCALEfcn(DATA) >= SCALE(k)) & (SCALEfcn(DATA) < SCALE(k+1)))];
end
I still do not understand what you want. This sort of histogram approach is as close as I can get.
Experiment with it to get different results.
Hans123
Hans123 2020 年 5 月 29 日
Thank you for your time, I really appreciate it. I can tinker around with the helpful lines you have given me. I am glad to hear from you during these uncertain times. As always, thank you for the help Star Strider. Always a blessing to have you in this forum!
Star Strider
Star Strider 2020 年 5 月 29 日
As always, my pleasure!
Thank you very much for your compliments and sentiments!

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