stepwise mean value of array
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Hi!
% a= [1 2 5 6 4 7......]
how to get the mean value :
mean_a =[mean(a(1),a(110)),mean(a(2),a(120)), mean(a(3),a(130))............]
thanky
2 件のコメント
Image Analyst
2012 年 11 月 14 日
What do you mean by mean(a(1),a(110))? Is that the mean of all elements from 1 to 110, like this: mean(a(1:110))?
採用された回答
Jan
2012 年 11 月 14 日
x = rand(1, 1000);
index1 = 1:10;
index2 = 100:100:1000;
result = (x(index1) + x(index2)) * 0.5;
0 件のコメント
その他の回答 (3 件)
Dian Permatasari
2012 年 11 月 14 日
if the calculation of some matrix, you can use:
B=mean([A(1) A(2) A(3) ...])
0 件のコメント
Walter Roberson
2012 年 11 月 14 日
N = 7; %or as appropriate
LB = 1 : N; %the lower bounds for the means
UB = (1:N)*100; %or as appropriate for the upper bound
S = cumsum(a); %the trick!
mean_a = (S(UB) - S(LB)) ./ (UB - LB + 1);
0 件のコメント
Andrei Bobrov
2012 年 11 月 14 日
編集済み: Andrei Bobrov
2012 年 11 月 14 日
"...the mean value of element 1 and element 100, and the mean value of element 2 and element 200 an so on..." :
k = 100:100:numel(a);
mean_a = mean(a([(1:numel(k))', k']),2);
0 件のコメント
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