Counting the year in julian dates

1 回表示 (過去 30 日間)
Katie
Katie 2012 年 11 月 13 日
回答済み: Tom W 2014 年 7 月 29 日
I need to ask for the hire date and current date of an employee, convert it to julian date, and spit out how many days they've worked there. I know how to figure out julian date in days. How do I take care of the year issue?
  1 件のコメント
James Tursa
James Tursa 2012 年 11 月 13 日
My guess is you are confusing Julian Date with day-of-the-year. Can you please provide a specific example of inputs and desired output?

サインインしてコメントする。

回答 (1 件)

Tom W
Tom W 2014 年 7 月 29 日
You don't need julian days, all you need is today() minus hire date (with format). Difference in days will be the output.
or
gregorian("ThisYear", "ThisMonth", "ThisDay") - gregorian(Yr1,Mo1,Day1);

カテゴリ

Help Center および File ExchangeDates and Time についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by